Hey guys,

How do I find the range of f(x,y)=sqrt(9-x^2-y^2)?

Thanks for the help!

mathmeme
Aug 4, 2017

#1**+1 **

How do I find the range of f(x,y)=sqrt(9-x^2-y^2)

\(\sqrt{9-x^2-y^2}\\ =\sqrt{9-(x^2+y^2)}\\ \text{So for real solutions}\\ x^2+y^2\le9\\ -3\le x \le3\qquad and \qquad -3\le y\le3\\ \text{The range is } -3\le y\le 3\)

Melody
Aug 4, 2017