+817 I have tried to solve this problem. Can anyone help?
Three runners, Dirk, Edith, and Foley all start at the same time for a $24$ km race, and each of them runs at a constant speed. When Dirk finishes the race, Edith is $5$ km behind, and Foley is $6$ km behind. When Edith finishes the race, how far behind is Foley, in km?
+129771 When Dirk finishes the race Foley has run 24 - 6 = 18 km and Edith has run 24 - 5 = 19km
So Foley runs 18/19 of the distance that Edith runs
When Edith finishes the race, she has run 24 km and he has run 24 * (18/19) = 432 / 19 km
So....he is 24 - 432 / 19 = 24/19 km behind ≈ 1.26 km behind
