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idk how to do this.

i tried dividng by 4 but i am pretty sure that is wrong.

also, i am still a bit confuse on what to do if the problem include the word “inverse”... if you can explain this too that will be great!!



 Oct 10, 2018

\(\dfrac{y_2}{y_1}=\dfrac{1}{\sqrt{\dfrac{x_2}{x_1}}}\\y_2 = \dfrac{1}{\sqrt{\dfrac{x_2}{x_1}}}y_1 \\ 1 = \dfrac{1}{\sqrt{\dfrac x 2}} 4 \\ 1 = 4 \sqrt{\dfrac 2 x}\\ 1 = 16 \dfrac 2 x \\ x = 32 \)

 Oct 10, 2018

Find the  proportionality constant,  k


y  = k / √x


4  = k / √2


4√2  = k   = √32




1 =  √32 / √x


√x  = √32


x  = 32



cool cool cool

 Oct 10, 2018

Thanks!! But I am still confuse what “inverse” really is and does in this problem...

 Oct 10, 2018

Inversely proportional simply means that as one gets bigger the other gets smaller.


so  if y is inversely proportional to x then 

y= k/x      (k is just a constant)


here y is inverserely proportional to sqrt(x)     so


y = k/ sqrt(x)

 Oct 11, 2018


How did it get smaller? How does this get smaller: y = k/sqrt(x). So this is how I am suppose to solve inverse problems? Doing/using this formula/work?

Guest Oct 12, 2018

Yes you use this fact

Let k be a constant that you will often need to find using information from the question.


If y is directly proportional to x then    




If you graph x agains y you will get a straight line.  

The y interept is 0

aand the gradient is k




If y is inversely proportional to x then 




This time if you graph it it will be a hyperbola. 

If k is positive it will be in the first and 3rd quad

and if k is neg it will be in the 2nd and 4th quads.


Now consider the case there k is +1

If x=2    y=1/2

If x=4     y=1/4

See, as x gets bigger, y gets smaller.   (that is when k is positive)

Melody  Oct 12, 2018

In your question, y varies inversly to sqrtx

so you must start with:




then sub in (2,4) to determine the value of k


Once you have k then you have a formula that you can use for determining the y value of any x value.

Melody  Oct 12, 2018

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