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If ,\(\frac{3x^2-4x+1}{x-1}=m\) and \(x\) can be any real number except 1 , what real values can \(m\) NOT have?

 Aug 13, 2021
 #1
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Uisng the quadratic formula, m can be any value except 4.

 Aug 13, 2021
 #2
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If \(\frac{3x^2-4x+1}{x-1}=m, \)  and x  can be any real number except 1 , what real values can  m NOT have?

 

Hello Guest!

 

\((m(x)=\frac{3x^2-4x+1}{x-1})\color{blue}\in\mathbb R\ |\ x\neq 1\\ m(1)\ is\ not\ 2\\ \color{blue}2\notin \{m(x)\} \)  

laugh

 Aug 13, 2021

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