If ,\(\frac{3x^2-4x+1}{x-1}=m\) and \(x\) can be any real number except 1 , what real values can \(m\) NOT have?
Uisng the quadratic formula, m can be any value except 4.
If \(\frac{3x^2-4x+1}{x-1}=m, \) and x can be any real number except 1 , what real values can m NOT have?
Hello Guest!
\((m(x)=\frac{3x^2-4x+1}{x-1})\color{blue}\in\mathbb R\ |\ x\neq 1\\ m(1)\ is\ not\ 2\\ \color{blue}2\notin \{m(x)\} \)
+140 
