+206 What is the sum of the $x$-values that satisfy the equation $5=\frac{x^3-2x^2-8x}{x+2}$?
+37146 x cannot = 2 ( from the denominator)
NUMERATOR factors to x ( x+2)(x-4) the (x+2) in the numerator and denominator cancel and you are left with:
x^2 - 4x = 5
x^2 - 4x - 5 = 0
(x-5)(x+1) = 0 so x = 5 or -1 sum = 4
+240 \(5=\frac{x^3-2x^2-8x}{x+2}\)
\(5=x\left(x-4\right)\)
\(x=5,\:x=-1\)
\(5+\left(-1\right)\)
\(=5-1\)
\(=4\)
