+0  
 
-1
58
2
avatar+204 

What is the sum of the $x$-values that satisfy the equation $5=\frac{x^3-2x^2-8x}{x+2}$?

 Feb 24, 2021
 #1
avatar+31204 
+1

x cannot = 2   ( from the denominator)

 

NUMERATOR   factors to   x ( x+2)(x-4)       the (x+2) in the numerator and denominator cancel and you are left with:

x^2 - 4x = 5

x^2 - 4x - 5 = 0

(x-5)(x+1) = 0       so x = 5 or -1          sum = 4

 Feb 24, 2021
 #2
avatar+266 
0

\(5=\frac{x^3-2x^2-8x}{x+2}\)

 

\(5=x\left(x-4\right)\)

 

\(x=5,\:x=-1\)

 

\(5+\left(-1\right)\)

 

\(=5-1\)

 

\(=4\)

 

cheekycheekycheeky

.
 Feb 25, 2021

58 Online Users

avatar
avatar
avatar
avatar