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The average cost per unit C(x), in dollars, to produce x units of toy cars is given by C(x)=(8000)/(x−50)C(x)=(8000)/(x−50). What is the approximate cost per unit when 1250 toy cars are produced?

Guest Aug 20, 2017
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Intepretation: Approx for \(x\) in the function \(C(x)=\frac{8000}{x-50}\) when \(C(x)=1250\)

 Solution:

Solve for \(x\) when \(\frac{8000}{x-50}=1250\)

Multiple both sides by a factor of \(x-50\):

\(1250(x-50)=8000\)

Expand:

\(1250x-62500=8000\)

Move the numerical term to the right:

\(1250x=70500\)

Divide both sides by the greatest common divisor of \(1250\) and \(70500\) (Which is equal to \(250\))

\(5x=282\)

Divide both sides by \(5\):

\(x =\frac{282}{5}\)

\(=56.4 \approx 56\)

Done :D

(You accidently posted the formula for \(C(x)\) in your question two times, be careful.)

Jeffes02  Aug 20, 2017

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