#1**+5 **

To remove the radical from the denominator, multiply both the numerator and the denominator by a value that makes the denominator whole.

If the denominator is cube root(a) multiply the numerator and denominator by cube root(a²).

The numerator becomes the cube root(a²) while the denominator becomes the cube root(a³), which is just a.

So the answer is: cube root(a²) / a.

geno3141
Sep 25, 2014

#2**+5 **

Best Answer

$$\\\dfrac{1}{\sqrt[3]{a}}\\\\\\

=\dfrac{1}{a^{1/3}}\\\\\\

=\dfrac{1}{a^{1/3}}\times \dfrac{a^{2/3}}{a^{2/3}}\\\\\\

=\dfrac{a^{2/3}}{a^{1/3+2/3}}\\\\\\

=\dfrac{a^{2/3}}{a^{1}}\\\\\\

=\dfrac{\sqrt[3]{a^2}}{a}\\\\\\

$Which is exactly what geno said in the first place! $$$

Melody
Sep 26, 2014