+1124 Hi good people!,
This problem I bet is simple and straight forward, but I cannot wrap my brain around this..please help:
A rectangle has a length that is 16cm more than it's breadth. If the length and breadth are in the ratio 4:3, determine the length and breadth of the rectangle..
I did this bet get stuck:
\({length \over Breadth}={4 \over 3}={x+16 \over y}\)
that gives:
\(4y=3x+48\)
Now...I'm stuck.. 
Let the width of the rectangle = W
Then the length of the rectangle = W + 16
[W + 16] / W = 4 / 3, solve for W cross multiply
[W + 16] = 4 / 3W Subtract W frm both sides
16 = 4 / 3W - W
16 = 1 / 3W divide both sides by 1/3
W = 16 / (1/3)
W = 16 x 3
W = 48 cm - the width of the rectangle
48 + 16 = 64 cm - the length of the rectangle. So that:
64:48 = 4:3
+1124 Hi guest,
sorry for replying only now, thanx a lot,you have helped me see my error..thanx again..
+118689 Hi Juriemagic,
Your y is equal to x.
The length and bredth are x and x+16
