Hi good people!,

This problem I bet is simple and straight forward, but I cannot wrap my brain around this..please help:

A rectangle has a length that is 16cm more than it's breadth. If the length and breadth are in the ratio 4:3, determine the length and breadth of the rectangle..

I did this bet get stuck:

\({length \over Breadth}={4 \over 3}={x+16 \over y}\)

that gives:

\(4y=3x+48\)

Now...I'm stuck..

juriemagic
Apr 23, 2018

#1**+1 **

Let the width of the rectangle = W

Then the length of the rectangle = W + 16

[W + 16] / W = 4 / 3, solve for W cross multiply

[W + 16] = 4 / 3W Subtract W frm both sides

16 = 4 / 3W - W

16 = 1 / 3W divide both sides by 1/3

W = 16 / (1/3)

W = 16 x 3

W = 48 cm - the width of the rectangle

48 + 16 = 64 cm - the length of the rectangle. So that:

64:48 = 4:3

Guest Apr 23, 2018

edited by
Guest
Apr 23, 2018

#3**0 **

Hi guest,

sorry for replying only now, thanx a lot,you have helped me see my error..thanx again..

juriemagic
Apr 23, 2018