+0  
 
0
308
1
avatar+8 

The resistance, R (in ohms) of a wire varies directly with the length, L (in cm) of the wire, and inversely with the cross-sectional area, A (in cm^2). A 500 cm piece of wire with a radius of 0.2cm has a resistance of 0.025 ohm. Find an equation that relates these variables in the form of \(R = \frac {\square\cdot \pi\cdot L}{\square}\)

BillHicks1207  Apr 5, 2017
 #1
avatar+7481 
+2

The resistance, R (in ohms) of a wire varies directly with the length, L (in cm) of the wire, and inversely with the cross-sectional area, A (in cm^2). A 500 cm piece of wire with a radius of 0.2cm has a resistance of 0.025 ohm. Find an equation that relates these variables in the form of  \(R=\frac{\Box \cdot \pi \dot\ L}{\Box}\)

 

 

\(R=\rho\times \frac{L}{A}\)

 

\(R[\Omega]=\rho[\frac{\Omega \cdot mm^2}{m}]\times \frac{L[m]}{\pi\cdot r^2[mm^2]}\)

 

example

\(R=0,025\Omega\)

\(r=2 mm\)

\(L=0.5 m\)

 

\(\rho=\frac{A\cdot R}{L}=\frac{r^2\pi\cdot R}{L}=\frac{2^2mm^2\cdot \pi \cdot 0.025\Omega}{0.5m}\color{blue}=0.62832\frac{\Omega \cdot mm^2}{m}\)    [ stainless steel ]

 

laugh  !

asinus  Apr 5, 2017

20 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.