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write and find 2 mixed numbers so the rules apply,

1:one number is larger than the other by 4 2/3
2:The difference of the numbers is equal to the smaller number.
3:The sum of the numbers is natural number.

Guest Nov 12, 2017
edited by Guest  Nov 12, 2017

#1
+6955
+2

Let's call the larger number  L , and the smaller number  S .

1.     L  =  S + 4$$\frac23$$

2.     L - S  =  S

Substitute  S + 4$$\frac23$$  in for  L .

S + 4$$\frac23$$  -  S  =  S

Cancel the  S  and  -S  on the left side.

$$4\frac23$$  =  S

L  =  S + 4$$\frac23$$

Substitute  4$$\frac23$$  in for  S .

L  =  4$$\frac23$$  +  4$$\frac23$$

L  =  8 +  $$\frac43$$

L  =  8 +  $$\frac33$$ +  $$\frac13$$

L  =  9$$\frac13$$

And...let's check that their sum is a natural number.

L + S   =   9$$\frac13$$  +  4$$\frac23$$   =   13 $$\frac33$$   =   14   Yep!

hectictar  Nov 12, 2017
Sort:

#1
+6955
+2

Let's call the larger number  L , and the smaller number  S .

1.     L  =  S + 4$$\frac23$$

2.     L - S  =  S

Substitute  S + 4$$\frac23$$  in for  L .

S + 4$$\frac23$$  -  S  =  S

Cancel the  S  and  -S  on the left side.

$$4\frac23$$  =  S

L  =  S + 4$$\frac23$$

Substitute  4$$\frac23$$  in for  S .

L  =  4$$\frac23$$  +  4$$\frac23$$

L  =  8 +  $$\frac43$$

L  =  8 +  $$\frac33$$ +  $$\frac13$$

L  =  9$$\frac13$$

And...let's check that their sum is a natural number.

L + S   =   9$$\frac13$$  +  4$$\frac23$$   =   13 $$\frac33$$   =   14   Yep!

hectictar  Nov 12, 2017

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