write and find 2 mixed numbers so the rules apply,
1:one number is larger than the other by 4 2/3
2:The difference of the numbers is equal to the smaller number.
3:The sum of the numbers is natural number.
Let's call the larger number L , and the smaller number S .
1. L = S + 4\(\frac23\)
2. L - S = S
Substitute S + 4\(\frac23\) in for L .
S + 4\(\frac23\) - S = S
Cancel the S and -S on the left side.
\(4\frac23\) = S
L = S + 4\(\frac23\)
Substitute 4\(\frac23\) in for S .
L = 4\(\frac23\) + 4\(\frac23\)
L = 8 + \(\frac43\)
L = 8 + \(\frac33\) + \(\frac13\)
L = 9\(\frac13\)
And...let's check that their sum is a natural number.
L + S = 9\(\frac13\) + 4\(\frac23\) = 13 \(\frac33\) = 14 Yep!
Let's call the larger number L , and the smaller number S .
1. L = S + 4\(\frac23\)
2. L - S = S
Substitute S + 4\(\frac23\) in for L .
S + 4\(\frac23\) - S = S
Cancel the S and -S on the left side.
\(4\frac23\) = S
L = S + 4\(\frac23\)
Substitute 4\(\frac23\) in for S .
L = 4\(\frac23\) + 4\(\frac23\)
L = 8 + \(\frac43\)
L = 8 + \(\frac33\) + \(\frac13\)
L = 9\(\frac13\)
And...let's check that their sum is a natural number.
L + S = 9\(\frac13\) + 4\(\frac23\) = 13 \(\frac33\) = 14 Yep!