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0
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Thereis x. If you add 

30/7

 to it, from the sum you get subtract

22/7

, and then subtract that difference from

59/7

, then you will get

19/7
what is x?
smiley

 Nov 12, 2017

Best Answer 

 #3
avatar+7352 
+1

\(\frac{59}{7}-[(x+\frac{30}{7})-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-[x+\frac{30}{7}-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-x-\frac{30}{7}+\frac{22}{7}=\frac{19}{7} \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}=\frac{19}{7}+x \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}-\frac{19}{7}=x \\~\\ \frac{32}{7}=x\)

.
 Nov 12, 2017
 #1
avatar
0

PLEASE SOLVE!!!!!!!!!!!!!!!!!!!!!!

 Nov 12, 2017
 #2
avatar
0

hint:answer is not 70/7 or 10

 Nov 12, 2017
 #3
avatar+7352 
+1
Best Answer

\(\frac{59}{7}-[(x+\frac{30}{7})-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-[x+\frac{30}{7}-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-x-\frac{30}{7}+\frac{22}{7}=\frac{19}{7} \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}=\frac{19}{7}+x \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}-\frac{19}{7}=x \\~\\ \frac{32}{7}=x\)

hectictar Nov 12, 2017
 #4
avatar
+1

thanks

 Nov 12, 2017

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