+0

0
149
4

30/7

to it, from the sum you get subtract

22/7

, and then subtract that difference from

59/7

, then you will get

19/7
what is x?

Guest Nov 12, 2017

#3
+6955
+1

$$\frac{59}{7}-[(x+\frac{30}{7})-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-[x+\frac{30}{7}-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-x-\frac{30}{7}+\frac{22}{7}=\frac{19}{7} \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}=\frac{19}{7}+x \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}-\frac{19}{7}=x \\~\\ \frac{32}{7}=x$$

hectictar  Nov 12, 2017
Sort:

#1
0

Guest Nov 12, 2017
#2
0

hint:answer is not 70/7 or 10

Guest Nov 12, 2017
#3
+6955
+1

$$\frac{59}{7}-[(x+\frac{30}{7})-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-[x+\frac{30}{7}-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-x-\frac{30}{7}+\frac{22}{7}=\frac{19}{7} \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}=\frac{19}{7}+x \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}-\frac{19}{7}=x \\~\\ \frac{32}{7}=x$$

hectictar  Nov 12, 2017
#4
+1

thanks

Guest Nov 12, 2017

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