+0  
 
0
191
4
avatar

 

Thereis x. If you add 

30/7

 to it, from the sum you get subtract

22/7

, and then subtract that difference from

59/7

, then you will get

19/7
what is x?
smiley

Guest Nov 12, 2017

Best Answer 

 #3
avatar+7096 
+1

\(\frac{59}{7}-[(x+\frac{30}{7})-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-[x+\frac{30}{7}-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-x-\frac{30}{7}+\frac{22}{7}=\frac{19}{7} \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}=\frac{19}{7}+x \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}-\frac{19}{7}=x \\~\\ \frac{32}{7}=x\)

hectictar  Nov 12, 2017
 #1
avatar
0

PLEASE SOLVE!!!!!!!!!!!!!!!!!!!!!!

Guest Nov 12, 2017
 #2
avatar
0

hint:answer is not 70/7 or 10

Guest Nov 12, 2017
 #3
avatar+7096 
+1
Best Answer

\(\frac{59}{7}-[(x+\frac{30}{7})-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-[x+\frac{30}{7}-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-x-\frac{30}{7}+\frac{22}{7}=\frac{19}{7} \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}=\frac{19}{7}+x \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}-\frac{19}{7}=x \\~\\ \frac{32}{7}=x\)

hectictar  Nov 12, 2017
 #4
avatar
+1

thanks

Guest Nov 12, 2017

6 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.