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So, I'm really bad at math, I was wondering if you guys could help me out with this question...

18 r s to the 0'th power t to 9th power over.

6 r to the 8th s to seventh and t to the fourth.

 Apr 14, 2015

Best Answer 

 #1
avatar+118677 
+10

18 r s to the 0'th power t to 9th power over.

r to the 8th s to seventh and t to the fourth.

 

$$\\\dfrac{18rs^0t^9 }{ 6r^8s^7t^4}\\\\

=\dfrac{3rt^9 }{ r^8s^7t^4}\\\\

=\dfrac{3t^{9-4} }{ r^{8-1}s^7}\\\\

=\dfrac{3t^{5} }{ r^{7}s^7}\\\\$$

 Apr 14, 2015
 #1
avatar+118677 
+10
Best Answer

18 r s to the 0'th power t to 9th power over.

r to the 8th s to seventh and t to the fourth.

 

$$\\\dfrac{18rs^0t^9 }{ 6r^8s^7t^4}\\\\

=\dfrac{3rt^9 }{ r^8s^7t^4}\\\\

=\dfrac{3t^{9-4} }{ r^{8-1}s^7}\\\\

=\dfrac{3t^{5} }{ r^{7}s^7}\\\\$$

Melody Apr 14, 2015
 #2
avatar-6 
+3

its o and it is easy took me about 3 seconds

 Apr 14, 2015

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