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In a TV set, an electron beam moves with horizontal velocity of 4.2×10^7m/s across the cathode ray tube and strikes the screen, 45 cm away.The acceleration of gravity is 9.8 m/s2.How far does the electron beam fall while traversing this distance?Answer in units of m.

 Oct 5, 2020
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Find out how long it was travelling  

Horizontal @ 4.2 x 10^7 m/s   is constant

45 cm = .45 m

.45 m / 4.2 x 107 m/s = ........... seconds

 

Then to find the vertical distance

yf = yo + vo t - 1/2 (9.81 m/s2 ) t2

Yf is the distance you are looking for    yo = 0    vo= 0    

yf = -1/2 (9.81)(t2)    using the 't' you found in the first step

 Oct 5, 2020

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