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Bryan and Harold had 108 marbles altogether. Kaden gave away 1/2 as many marbles as what John gave away. The number of marbles John had left was the same as the number of marbles he had given away. If John had 1/2 as many marbles left as Kaden, how many marbles did John have at first?

 May 28, 2021
 #1
avatar+121004 
+1

How  do  Bryan  and  Harold   figure into  this   ????

 

 

cool cool cool

 May 28, 2021
 #2
avatar+33735 
+1

Yahhhh........!    LOL cheeky

ElectricPavlov  May 28, 2021
 #3
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Kaden and John had 108 marbles altogether. Kaden gave away 1/2 as many marbles as what John gave away. The number of marbles John had left was the same as the number of marbles he had given away. If John had 1/2 as many marbles left as Kaden, how many marbles did John have at first?

Guest May 28, 2021
 #4
avatar+1442 
+3

Bryan and Harold had 108 marbles altogether. Bryan gave away 1/2 as many marbles as Harold gave away. The number of marbles Harold had left was the same as the number of marbles he had given away. If Harold had 1/2 as many marbles left as Bryan, how many marbles did Harold have at first?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

B + H = 108

 

B gave = 1/2x marbles

H gave =  x  marbles

H had left x  marbles

B had left 2x marbles

 

1/2x + x + x + 2x = 108

x = 24

 

Harold had 48 marbles smiley

 May 28, 2021
edited by jugoslav  May 28, 2021

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