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 Jul 8, 2018
edited by Max0815  Jul 10, 2018
 #1
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Hint: How many permutations of three numbers{-1, 0, 1} can you arrange so that their SUM is always zero?

3! = {-1, 0, 1} | {-1, 1, 0} | {0, -1, 1} | {0, 1, -1} | {1, -1, 0} | {1, 0, -1} (total: 6). But since you have unlimited supply of these tiles, then {0, 0, 0} would also qualify?? Makes sense?

 Jul 8, 2018
 #2
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And then, each of the six tiles can be either blue or red (2 choices for each one of a set of 6 elements)

Guest Jul 8, 2018
 #3
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896 different ways

 Jul 8, 2018
 #4
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I'm still gtting it wrong. Can i have another hint?

 Jul 10, 2018
 #5
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Im having something like this: there are 6 choices for the first two, and 2 for the rest, but this is incorrect

 Jul 10, 2018
 #6
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Oh, ok, ive got it now! Thanks for the hint!

 Jul 10, 2018

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