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\({M}_{2}{R}_{3} + 3T{S}_{2} = 2M{S}_{3} + 3TR\)

M2R3 and TS2 are both ionic compounds. When 20.0 mL of a 1.0 M solution of M2R3 and 50 mL of a 1.0 M solution of TS2 are mixed, two precipitates are formed. After the Reaction has gone to completion, what ions remain in the solution?

 

A: M and R

B: T and S

C: M and S

D: T and R

 Dec 29, 2018
 #1
avatar+17331 
+2

You need  3:1  ts2  to m2r3 for a complete reaction.....

you have 50 ml of ts2   so you would need  16.67 ml of m2r3 for a complet reaction to occur.....you have 20-16.67 = 3.33 ml excess of m2r3 which will remain in solution         M and R  

 Dec 29, 2018
edited by ElectricPavlov  Dec 29, 2018
 #2
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Thank you so much! You guys are the best. See you again in a month or so ;)

Cent0rea88  Dec 29, 2018
 #3
avatar+17331 
+1

Enjoy your time away!  cheeky

ElectricPavlov  Dec 29, 2018

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