\({M}_{2}{R}_{3} + 3T{S}_{2} = 2M{S}_{3} + 3TR\)
M2R3 and TS2 are both ionic compounds. When 20.0 mL of a 1.0 M solution of M2R3 and 50 mL of a 1.0 M solution of TS2 are mixed, two precipitates are formed. After the Reaction has gone to completion, what ions remain in the solution?
A: M and R
B: T and S
C: M and S
D: T and R
You need 3:1 ts2 to m2r3 for a complete reaction.....
you have 50 ml of ts2 so you would need 16.67 ml of m2r3 for a complet reaction to occur.....you have 20-16.67 = 3.33 ml excess of m2r3 which will remain in solution M and R
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