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A 4" by 6" by 8" rectangular solid is cut by slicing through the midpoint of three adjacent edges. What is the number of inches in the sum of the lengths of the edges of the tetrahedron that is cut?

 Apr 28, 2017
 #1
avatar+9673 
+1

Use Pythagoras theorem to find the lengths of blue lines. 

Total length

= 4/2 + 6/2 + 8/2 + \(\sqrt{(\dfrac{4}{2})^2+(\dfrac{6}{2})^2}+\sqrt{(\dfrac{8}{2})^2+(\dfrac{4}{2})^2}+\sqrt{(\dfrac{6}{2})^2+(\dfrac{8}{2})^2}\)

= 2 + 3 + 4 + \(\sqrt{13}\) + \(2\sqrt{5}\) + 5

= 14 + sqrt(13) + 2sqrt(5)

 Apr 28, 2017
 #2
avatar+9479 
+1

Wow, you made this one look super easy breezy! Nice !!! laugh

hectictar  Apr 28, 2017
 #3
avatar+647 
0

i dont understand the answer

waffles  Apr 28, 2017

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