The length of a rectangle is increased to 2 times its original size and its width is increased to 3 times its original size. If the area of the new rectangle is equal to 1800 square meters, what is the area of the original rectangle?
+130071 Let the original length = L and the original width = W
So....after both increases we have that
2L * 3W = 1800
(2 * 3) * L * W =1800
6 L * W =1800 divide both sides by 6
L * W = 1800 / 6 = 300 m^2 = original area
+2096 Let's decide that the original length of a rectangle is x, and the original width is y.
We can write an equation.
2x times 3y = 1800
6xy=1800
xy=300
300 is the original area!
but flec got perfect score on IMO!!!
:omighty:
I am the humble Mat Hayden 
If the length of the rectangle is x2, and width is x3, then a trick is to note that the original rectangle can tile the new one 2*3=6 times. So if the new rectangle has an area of 1800 m^2, the original one would have an area of 1800/6=300 m^2.
+2096 I did NOT get a perfect score on the IMO, I didn't even enter 
Nice answer Math Hayden
