The length of a rectangle is increased to 2 times its original size and its width is increased to 3 times its original size. If the area of the new rectangle is equal to 1800 square meters, what is the area of the original rectangle?

Guest Feb 14, 2021

#1**+2 **

Let the original length = L and the original width = W

So....after both increases we have that

2L * 3W = 1800

(2 * 3) * L * W =1800

6 L * W =1800 divide both sides by 6

L * W = 1800 / 6 = 300 m^2 = original area

CPhill Feb 14, 2021

#2**+3 **

Let's decide that the original length of a rectangle is x, and the original width is y.

We can write an equation.

2x times 3y = 1800

6xy=1800

xy=300

300 is the original area!

CalTheGreat Feb 14, 2021

#4**+1 **

but flec got perfect score on IMO!!!

:omighty:

I am the humble Mat Hayden

If the length of the rectangle is x2, and width is x3, then a trick is to note that the original rectangle can tile the new one 2*3=6 times. So if the new rectangle has an area of 1800 m^2, the original one would have an area of 1800/6=300 m^2.

Guest Feb 14, 2021

#6**+2 **

I did NOT get a perfect score on the IMO, I didn't even enter

Nice answer Math Hayden

CalTheGreat
Feb 15, 2021