+0  
 
0
92
1
avatar

Let $a_n$ be a recursive function satisfying $a_n=a_{n-1}+2n-1$ for all positive integers $n$, and $a_0=0$. What is the value of $\displaystyle \sum _{n=1}^{100}a_n$?

 Feb 4, 2021
 #1
avatar
0

Notice that $a_n=n^2$. By the sum of squares formula, the answer is $\frac{100(100+1)(2*100+1)}{6}=\boxed{338350}$.

 Feb 4, 2021

26 Online Users

avatar
avatar
avatar