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Find the area of a regular pentagon with a side of 5cm round to nearest tenth

 

 Mar 6, 2021
 #1
avatar+197 
+3

Hey there!

 

The formula for the area of a pentagon is as follows:

 

\(Area=\frac{1}{4}\sqrt{5(5+2\sqrt{5})}*a^2\)

 

Since all sides are equal to 5cm, just sub this into "a" to get the area:
 

\(Area=\frac{1}{4}\sqrt{5(5+2\sqrt{5})}*5^2\approx43.01194cm^2\)

 

You want the nearest tenth so your answer will be: \(43.0cm^2\)

 

Hope this helped :)

 Mar 7, 2021
 #2
avatar+31212 
+1

Here is a way to solve:

 Mar 7, 2021

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