Find the area of a regular pentagon with a side of 5cm round to nearest tenth
+208 Hey there!
The formula for the area of a pentagon is as follows:
\(Area=\frac{1}{4}\sqrt{5(5+2\sqrt{5})}*a^2\)
Since all sides are equal to 5cm, just sub this into "a" to get the area:
\(Area=\frac{1}{4}\sqrt{5(5+2\sqrt{5})}*5^2\approx43.01194cm^2\)
You want the nearest tenth so your answer will be: \(43.0cm^2\)
Hope this helped :)
