The graph of y=h(x) is shown in red below. Compute h(h(7)).

(Assume grid lines are spaced 1 unit apart.)

The graph of y=f(x) is shown below in red. Given that f is invertible, find f^{-1}(4).

(Assume grid lines are spaced 1 unit apart.)

Guest Jun 25, 2019

#1**+2 **

First one

h(7) means that we go to "7" on the x axis....from here....we go * up* until we intercept the graph and we read the y value at that point....so.....going out to 7 and then going up we find that we intercept the graph at y = 5

So f(7) = 5

So f(f(7)) = f(5)

Then....we do the same thing.....go to 5 on the x axs and then go * down* until we intercept the graph at the y value of -1

So... f (f(7)) = f(5) = -1

Second one

f^{-1} (4) means that we go up on the graph until y = 4 and then we find the x value associated with that y value

So...when we go up to y = 4.....the x value asociated with this y value is 3

So

f^{-1}(4) = 3

CPhill Jun 25, 2019