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# Response to a question because that question is locked...

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Re: https://web2.0calc.com/questions/this-is-for-max

$$3\log(x - 2) = \log(2x) - 3\\ \log\left((x-2)^3\right)=\log\left(\dfrac{2x}{10^3}\right)\\ (x-2)^3=\dfrac{x}{500}\\ x^3 - 6x^2+12x-8 =\dfrac{x}{500}\\ 500x^3-3000x^2+5999x-4000=0\\ \text{The only real solution for x is }x = 2.162938888053492\\ \text{Luckily I have a cubic equation solver app XDDD}$$

MaxWong  Jun 4, 2017
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I unlocked the original Max so you can continue here or there, I guess it doesn't matter where.  :)

https://web2.0calc.com/questions/this-is-for-max

Melody  Jun 4, 2017