+0  
 
+1
87
4
avatar+206 

In how many ways can we choose 3 distinct letters of the alphabet, without regard to order, if we must choose 1 vowel (A, E, I, O, or U) and 2 consonants?

mathtoo  Feb 18, 2018
Sort: 

4+0 Answers

 #1
avatar+12266 
+2

Here we go....my stab at it....

5 ways to choose a vowel    a e i o u

   times    21c2

 

5 x 21c2 = 5 x 210 = 1050 ways

ElectricPavlov  Feb 18, 2018
 #2
avatar+2615 
+2

Hello, EP!

We have 5 options for the choice of the vowel, and we must make 2 choices out of the remaining 21 letters, for a total of \(\binom{21}{2} = 210\)choices for the consonants. This gives a total of \(5 \times 210 = \boxed{1050}\).

tertre  Feb 18, 2018
 #3
avatar+12266 
0

Thanx for the confirmation !  

ElectricPavlov  Feb 18, 2018
 #4
avatar+2615 
0

No problem, EP!

tertre  Feb 18, 2018

10 Online Users

avatar

New Privacy Policy (May 2018)

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see cookie policy and privacy policy.