rewrite the trig expression. assume u>0 and the value of the inner inverse trig expression; 0<theta<π/2

cos(tan-1 u)

Guest Jul 31, 2014

#1**+8 **

We want to find the cosine of a first quadrant angle whose tangent = u..... (or, u/1)

So we have....

cosΘ = 1/ √(1 + u^{2})

CPhill
Aug 1, 2014

#3**0 **

Nice triangle Melody! I like your answer.

Can somebody explain me this problem?

DragonSlayer554
Aug 1, 2014