rewrite the trig expression. assume u>0 and the value of the inner inverse trig expression; 0<theta<π/2
We want to find the cosine of a first quadrant angle whose tangent = u..... (or, u/1)
So we have....
cosΘ = 1/ √(1 + u2)
Nice triangle Melody! I like your answer.
Can somebody explain me this problem?