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In right triangle $DEF$, we have $\angle D = 25^\circ$, $\angle E = 90^\circ$, and $EF = 9$. Find $DE$ to the nearest tenth. You may use a calculator for this problem.

 Apr 22, 2021

Best Answer 

 #1
avatar+275 
+4

So here's the problem figure 

From figure, 

 

\(tan 25 = {EF \over DE}\)

\(0.47={9 \over DE}\)

\(DE=19.15\)

 

∴ Length of DE is 19.15 cm.

 Apr 22, 2021
 #1
avatar+275 
+4
Best Answer

So here's the problem figure 

From figure, 

 

\(tan 25 = {EF \over DE}\)

\(0.47={9 \over DE}\)

\(DE=19.15\)

 

∴ Length of DE is 19.15 cm.

amygdaleon305 Apr 22, 2021

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