A right triangle has legs of length 6 and b, and a hypotenuse of length c . The perimeter of the triangle is 24 . Compute c.
C is 10
With pythag, we have 6^2 + b^2 = c^2
36 + b^2 = c^2
c = \sqrt{36+b^2}
so now we have 6+b+\sqrt{36+b^2} = 24
After some ugly math, b=8
6^2 + 8^2 = c^2
100 = c^2
c = 10
check: 6^2 + 8^2 = 10^2
100 = 100
:)
Oh and perimeter check
10+8+6 = 14+10=24
6 + b + c = 24
b + c = 18
b = 18 - c
So....by the Pyth. theorem
6^2 + (18 - c)^2 = c^2
36 + c^2 - 36c + 324 = c^2
360 - 36c = 0 divide through by 36
10 - c = 0
