In right triangle ABC, M and N are midpoints of legs AB and BC, respectively. Leg AB is 6 units long, and leg BC is 12 units long. How many square units are in the area of triangle APC?
+14913 How many square units are in the area of triangle APC?
Hello Guest!
\(AN(x)=-x+6\\ MC(x)=-\frac{3}{12}x+3\\ -x+6=-\frac{1}{4}x+3\\ \color{blue}x=4 \)
\(A_{APC}=A_{ABC}-A_{BCM}-A_{AMP}\\ A_{APC}=\dfrac{12\cdot 6}{2}-\dfrac{12\cdot 3}{2}-\dfrac{3\cdot {\color{blue}4}}{2}\\ \color{blue}A_{APC}=12\)
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+2666 The area of the total triangle is \(6 \times 12 \div 2 = 36\)
Draw Median \(BO\). All 6 triangles have an area of 6
\(\triangle APC \) consists of exactly 2 of these triangles, meaning the area is \(2 \times 6 = \color{brown}\boxed{12}\)
