Rosalinda invested some of her $15,000 in bonds that made a 6% profit and the rest in bonds that made a 10% profit. If the profit on the 10% bonds was $1,000

Let's begin by writing algebraic expressions to represent the amount invested at each profit percentage:

    x = amount invested at 6% profit

    15,000 - x = remainder invested at 10% profit

Now let's write an equation using our algebraic expressions for the two invested amounts and the two profit percentages to express the relationship between the two profit amounts:

    Verbal Relationship:

        Profit Amount at 10% =

        Profit Amount at 6%   + $1,000

    Percent Conversion to Decimal:

        10% = 10/100 = 0.10
        6% = 6/100 = 0.06

    Algebraic Equation (our answer):

        0.10(15,000 - x) = (0.06)(x) + 1,000

Was I able to help you at all? :)

YES Thank you so much you are so helpful! :DDD

Aw. Thank you :)

I'm glad to be able to help you!! :)

Rosalinda invested some of her $15,000 in bonds that made a 6% profit and the rest in bonds that made a 10% profit. If the profit on the 10% bonds was $1,000 more than the profit on the 6% bonds, how much did Rosalinda invest in the 6% bonds

Let the amount of bonds @ 6%=B, then the balance,

15,000 - B=Bonds @ 10% interest

.10(15,000 - B) =.06B + 1,000

1,500 - .10B =.06B + 1,000

B=$3,125 Bonds at 6% interest rate.

$15,000 - $3,125 =$11,875 Bonds at 10% interest rate.

I like your answer and explanation!! :)

Good morn Hayley! Thanks for the compliment, but why didn't you finish your equation which was spot on?

My calculator died.. :(

Forgot to charge it...

and I figured that the person would know what to do from there :D