S over 3 - 4=2

Assuming your equation is as follows:

$${\frac{{\mathtt{s}}}{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{4}} = {\mathtt{2}}$$

Your goal is to isolate s in order to solve it. So first, add 4 to each side:

$${\frac{{\mathtt{s}}}{{\mathtt{3}}}} = {\mathtt{6}}$$

Now multiply both sides by 3:

$${\mathtt{s}} = {\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{6}} \Rightarrow {\mathtt{s}} = {\mathtt{18}}$$

*Edit: Ditto that, Ninja! :)

$$\frac{S}{3} -4 = 2$$

Add 4 to both sides to get rid of the -4 on the left side:

$$\frac{S}{3}=6$$

Multiply both sides by 3 to get rid of the /3 of the left side:

$$S = 6\times 3$$

$$S = 18$$

S/3 - 4 = 2   add 4 to both sides

S/3 = 6         multiply both sides by 3

S = 18

We have confirmed it....the answer is INDEED, 18...this is indisputable...no matter how you slice it....the answer is still, 18.....further testing is superfluous....the only theorem with more rigorous proof is the Pythagorean Theorem.....

That is all......

Goodnight.......

Haha, that's right CPhill. Pythagoras would be proud!