+0  
 
+1
289
4
avatar+117 

A student is offered two different summer jobs. Job A lasts 16 weeks and pays $400.00 per week. Job B lasts 4 months and pays $1,300.00 per month, with monthly raises of 10% of the previous month's salary. How much more does the student earn by accepting Job A (rounded to the nearest cent)?

 $366.70

 $264.00

 $675.50

 $680.00

It's not C lol

failurewithasmile  Apr 14, 2017
 #1
avatar+1508 
+2

Hang on tight Im tryin to figure these q's out

MysticalJaycat  Apr 14, 2017
 #2
avatar+1508 
+3

I would estimate on 366.70 frown

MysticalJaycat  Apr 14, 2017
 #3
avatar+87564 
+2

Pay for "A"   - Pay for "B"   =

 

16 *400  - [ 1300  + 1300(1.10) + 1300(1.10)^2 + 1300(1.10)^3]  =

 

 

$366.70  .......just as MJ  found......!!!!!

 

 

 

cool cool cool

CPhill  Apr 15, 2017
 #4
avatar+92882 
0

deleted - added on a new question.

Melody  Apr 15, 2017
edited by Melody  Apr 15, 2017

6 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.