Samir has a 23-link chain. He wants to cut and disengage the minimum number of links so that any number of links from 1 to 23 can be obtained by taking one or more of the resulting pieces (including the disengaged links). Give the position(s) of the link(s) he must cut.
1. First cut must be at the 3-rd link. Then Samir has this 3-rd link cut as a single link; he has also the block of 2 links (the 1-st and the 2-nd links connected together); and then he has 3 links as the union ((1st + 2nd together) U 3rd).
2. Next cut must be at the 8-th link. Then, in addition to the set (A), Samir has - this 8-th link cut; - the block of 4 links (4th+5th+6th+7th all connected together), and then it is clear that combining this block of 4 links with what he just has in the set (A), he is able to have a) 4 links; b) 5=4+1 links; c) 6=4+2 links; d) 7=4+3 links; and e) 8=4+3+1(8th) links.
3. By continuing with this pattern, it is clear that (C) the next, third cut must be at the 8 + 8 + 1 = 17-th link.
4. The next (and the last), fourth cut must be at the 17 + 3 = 20-th link. Then it is OBVIOUS that having the sets (A), (B), (C) and additional 2 connected segments (18,19) and (21,22,23) and 1 cut link (20th) Samir will be able to present a) 18 = 17 +1; b) 19 = 17+2; c) 20 = 17+2+1; d) 21=17+3+1; e) 22=17+2+3; and, finally, all 23 links as well.
So, the problem is just solved and the ANSWER is: The cuts should be made at 3-rd; 8-th; 17-th; and 20-th links.
Hope this helped!
( ゚д゚)つ Bye