(x-6)2 +(y-3)2 = 25
the equation above is a circle. If the circle is translated downward a usits such that the circle is tangent tot he x-axis, the equation becomes (x-6)2 +(y-3+a)2 = 25. What is the value of a.
To make the x axis a tangent of a do we not need to make the edge of the circle touch the x-axis? That is changing the number with the y component. the radius id the root of the number on the other side of the equations. so the radius is 5. And to get the circles edge to tought the x axis it needs to be 5 places away from it. So wouldnt a = -2?
I typed that in and it said that it was the wrong answer? why?
By entering -2, you made the y-component to be (y - 5)2 which would make the circle tangent to the x-axis --
and the circle will be above the x-axis (center at (6,5) -- however, you were instructed to translate the circle
downwards -- by making a = 5, you translated the circle upwards.
You will need the y-component to be (y + 5)2 -- which will make the circle tangent to the x-axis -- it will
be tangent below the x-axis.