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I have this question : A school bought a certain amount of books and paid 140 for them all, if the price of each book costed 0.3\$ less the school would get atleast more 6 books than what it got, find in what range should be the quantity of books. I translated this on my own- now i built this formula ((140/x)-.03)*(x+y)=140 if you place 6 instead of y you'll get the minimum books quantity which is 50, now the range should be 50 min to 466 max , can't figure out how to get the max value!

Guest Apr 11, 2017
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I think your question is faulty. There is something missing! This range business between 50 and 466 doesn't make sense!! If you want to get 466, then just divide 140/0.30 ~466. But even that doesn't make any sense! Here is my attempt at solving it from the information you have given:

Assume number of books=N
Assume cost of each book =D
140/D =N,
N / (D - 0.30) =N+6, solve for D, N (I assumed 0.30, to be 30 cents less per book)
N=112 Books, and
D =\$1.25 per book

P.S. You get fractions in N, or number of books, which you shouldn't.

Guest Apr 11, 2017