+0  
 
0
106
1
avatar+33 

Mel rolls a .01kg marble down a ramp and off the edge of a table with a horizontal velocity of 1.2m/s. The marble hits a target placed .51m from the table's edge. How high is the table?

KingChris  Dec 20, 2017
Sort: 

1+0 Answers

 #1
avatar+86649 
+1

The horizontal velocity is unaffected by the drop..   also ....the weight of the marble is irrelevant..so....

 

The time it takes to drop  =  d / r  =    .51 m / 1.2 m/s   =  .425 s

 

So......the height of the table can be found  as

 

H  =  vi * t   +  (1/2) a  * t^2

 

Where  

 

H  =  the table height

vi =  the intital vertical velocity =  0

t  =  time to drop  =   .425 s

a  =  acceleration due to gravity =  9.81 m/s^2

 

So we have

 

H  =  0 * .425s +  (1/2) (9.81m/s^2) * (.425s)^2  

 

H  ≈   .886 m

 

 

cool cool cool

CPhill  Dec 20, 2017

11 Online Users

avatar

New Privacy Policy (May 2018)

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see cookie policy and privacy policy.