Mel rolls a .01kg marble down a ramp and off the edge of a table with a horizontal velocity of 1.2m/s. The marble hits a target placed .51m from the table's edge. How high is the table?
The horizontal velocity is unaffected by the drop.. also ....the weight of the marble is irrelevant..so....
The time it takes to drop = d / r = .51 m / 1.2 m/s = .425 s
So......the height of the table can be found as
H = vi * t + (1/2) a * t^2
H = the table height
vi = the intital vertical velocity = 0
t = time to drop = .425 s
a = acceleration due to gravity = 9.81 m/s^2
So we have
H = 0 * .425s + (1/2) (9.81m/s^2) * (.425s)^2
H ≈ .886 m