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Mel rolls a .01kg marble down a ramp and off the edge of a table with a horizontal velocity of 1.2m/s. The marble hits a target placed .51m from the table's edge. How high is the table?

KingChris  Dec 20, 2017
 #1
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The horizontal velocity is unaffected by the drop..   also ....the weight of the marble is irrelevant..so....

 

The time it takes to drop  =  d / r  =    .51 m / 1.2 m/s   =  .425 s

 

So......the height of the table can be found  as

 

H  =  vi * t   +  (1/2) a  * t^2

 

Where  

 

H  =  the table height

vi =  the intital vertical velocity =  0

t  =  time to drop  =   .425 s

a  =  acceleration due to gravity =  9.81 m/s^2

 

So we have

 

H  =  0 * .425s +  (1/2) (9.81m/s^2) * (.425s)^2  

 

H  ≈   .886 m

 

 

cool cool cool

CPhill  Dec 20, 2017

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