There are 8 identical chairs around a circular table. In how many ways can 5 people be seated in 5 of these chairs if Richard wants to sit next to either Surya or Tamas (or both Surya and Tamas)?
(Consider two seating arrangements to be the same if one seating arrangement can be rotated to obtain the other.)
So one possible method is complementary counting but i can't really get the answer from that
+129839 Here's my attempt
Let's let the positions around the table look like this
R ___ ____ _____ _____ ______ ______ ____
1 2 3 4 5 6 7 8
Richard sits in chair 1
Position 2 is just to the right of Richard and position 8 is just to his left
Case 1 - Surya wants to sit on his right (in chair 1) but Tamas does not occupy the chair on his left
Tamas can choose any chair in the positions 3 - 7 and she will not sit next to Richard = 5 choices
And the other 2 people can can occupy the remaining seats in P(5,2) = 20 ways
This gives us 5 *20 = 100 ways
Case 2 - Surya wants to sit on his left (in Chair 8) but Tamas does not occupy the chair to his right
Again, Tamas can shoose any chair in positions 3 -7 and she will agian not sit next to Richard = 5 choices
And again, the other two people can occupy the remaining seats in P( 5,2) = 20 ways
This again gives us 100 ways
So far, this = 200 ways
The cases where Tamas sits either to his right or left but Surya does not sit next to him also gives us 200 ways
So...we have 400 ways, so far
Case 3 - both sit next to him (in chairs 2 and 8)
This can be done in two ways and for each of these the other two people can occupy any two of the positions 3-7 in
P(5,2) =20 ways
So this arrangement = 2 * 20 = 40 ways
So....the total ways in which either one (or both) sit next to him =
200 (2) + 40 = 440 ways
