+69 In the adjoining figure, CD is the diameter of a semicircle with center O. Point A lies on the extension of DC past C; point E lies on the semicircle, and B is the point of intersection (distinct from E) of line segment AE with the semicircle. If length AB equals length OD, and the measure of angle EOD is 45 degrees, then find the measure of angle BAO, in degrees.
+1641 ∠CED = 90º ∠ADE = 67.5º ∠ACE = 90 + 67.5 = 157.5º
∠BAO + ∠AEC = 180 - 157.5 = 22.5º
∠BAO : ∠AEC = 2 : 1
Angle BAO = 15 degrees 
+129907 Hey, jugoslav.....could you show how you solved this ???
I couldn't figure out any way to solve it 
