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There is a 6-digit sequence of 8 positive consecutive integers that divides 2, 3, 5, 7, 9, 11, 13 and 17 EVENLY. What is the sequence in question? Thank you for help.

 Nov 23, 2019
 #1
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This is a job for a computer code to find! How else can you test 10,000,000 numbers for a sequence of 8 consecutive integers? So, here is your computer code to do just that.


a=1; b=10000000;c=if(a%2==0 and (a+1)%3==0 and (a+2)%5==0 and (a+3) %7==0 and (a+4)%9 and (a+5)%11==0 and (a+6)%13==0 and (a+7)%17==0, goto loop, goto next); loop:printa," ",;next: a++;if(a


OUTPUT- There is no 6-digit sequence that the computer could find !!  However, it found a 5-digit sequence of 8 integers as follows:(67568, 67569, 67570, 67571, 67572, 67573, 67574, 67575)=67568 mod 2=0, 67569 mod 3=0, 67570 mod 5=0, 67571 mod 7 =0, 67572 mod 9 =0, 67573 mod 11 =0, 67574 mod 13 =0, 67575 mod 17 =0.


P. S. It also found 6 different sequences each made up of 7-digit integers as follows:
(1599098,  3130628,  4662158,  6193688,  7725218,  9256748) - Each of these sequences begins with the first term and each subsequent term is incremented by 1: Example: 1599098 , 1599099, 1599100, 1599101, 1599102, 1599103, 1599104, 1599105.

 Nov 23, 2019
 #2
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I do not understand the question

 

There is a 6-digit sequence of 8 positive consecutive integers that divides 2, 3, 5, 7, 9, 11, 13 and 17 EVENLY. What is the sequence in question? Thank you for help.

 

What does this mean....There is a 6-digit sequence of 8 positive consecutive integers     ??

 Nov 23, 2019

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