The Lucas numbers are defined in the same way, but with different starting values. Let L_0 be the zeroth Lucas number and L_1 be the first. If

L_0 = 2

L_1 = 1

L_n = L_(n - 1) + L_(n - 2)

then what is the 8th Lucas number? (Note: We seek a numerical answer.)

Guest Jan 4, 2022

#1**0 **

You have defined Lucas's numbers quite well. So, why are you having problems in finding the term that you want?

L(2) ==2 + 1==3

L(3)==1 + 3 ==4

L(4)==3 + 4 ==7

L(5)==4 + 7 ==11

L(6)==7 + 11 ==18

L(7)==11 + 18==29

**L(8)==18 + 29==47**

**Note: Your definition of Lucas's numbers, however, DOES NOT agree with other people's definition of Lucas's numbers!**

**For example: Wolfram/Alpha gives these as the first 10 terms:**

**1 | 2 | 3 | 4 | 7 | 11 | 18 | 29 | 47 | 76 (10 integers)**

Guest Jan 4, 2022