The fifth term of an arithmetic sequence is 9 and the 32nd term is 84. What is the 23rd term?
If the first term of an arithmetic sequence is a and the common difference is d,
then the fifth term is: a + 4d and the 32nd term is: a + 31 d.
We have these equations: a + 4d = 9
a + 31d = 84
Solving, we have: 27d = 75 ---> d = 75/27 = 25/9
which makes: a = -19/9
To find the 23rd term: a + 22d = -19/9 + 22(25/9) = ...