What is the integer value of x in the arithmetic sequence 3^2, x, 3^4*3^2?
3^2 , x, 3^4*3^2 =
3^2 , x , 3^6
Since this is arithmetic, the difference between successive terms is constant....so.....
x - 3^2 = 3^6 - x simplify
2x = 3^6 + 3^2
x = [ 3^6 + 3^2 ] / 2
x = 738 / 2
x = 369
Yessssssss right
been gone
That RIGHTTTT