An infinite geometric series has common ratio 1/8 and sum 80. What is the first term of the series?
+526 So it's given that r = 1/8 and S∞ = 80
∵ We know that,
\({S}_{∞} = {a\over 1-r}\)
\(80={a\over 1-{1\over 8}}\)
\(80={8a\over 7}\)
⇒ \(a=70\)
+526 So it's given that r = 1/8 and S∞ = 80
∵ We know that,
\({S}_{∞} = {a\over 1-r}\)
\(80={a\over 1-{1\over 8}}\)
\(80={8a\over 7}\)
⇒ \(a=70\)
