sheila has a total of 32 nickels and dimes worth $2.50. How many nickels does she have?

Guest Aug 3, 2014

#2**+5 **

I have interpreted this question differently.

Sheila has 32 coins all together. They are all nickels 5c and dimes 10c. There total value is $250

How many nickels does she have?

Let n be the number of nickels and let d be the number of dimes.

n+d=32 (1)

5n+10d=250 divide through by 5

n+2d=50 (2)

Solve equations 1 and 2 simultaneously. Start with (2)-(1)

$$\begin{array}{rlll}

n+2d&=&50\quad&(2)\\

\underline{n+d}&=&\underline{32}\quad&(1) Now \;subtract\\

d&=&18}

\end{array}\\\\

\begin{array}{rlll}

n+18&=&32\;\; therefore\\

n&=&14

\end{array}\\$$

check 14+18=32 and 5*14+10*18=70+180=250=$250 correct

So Sheila has 14 nickels

Melody Aug 3, 2014

#1**+5 **

I think you meant to put: How many dimes does she have?

Nickels are 5 cents: 32 nickels*0.05 [5 cents] = $1.60

$2.50 - $1.60 = $0.90

Dimes are 10 cents: 0.10*9 = $0.90 --> **Sheila has 9 dimes.**

AzizHusain Aug 3, 2014

#2**+5 **

Best Answer

I have interpreted this question differently.

Sheila has 32 coins all together. They are all nickels 5c and dimes 10c. There total value is $250

How many nickels does she have?

Let n be the number of nickels and let d be the number of dimes.

n+d=32 (1)

5n+10d=250 divide through by 5

n+2d=50 (2)

Solve equations 1 and 2 simultaneously. Start with (2)-(1)

$$\begin{array}{rlll}

n+2d&=&50\quad&(2)\\

\underline{n+d}&=&\underline{32}\quad&(1) Now \;subtract\\

d&=&18}

\end{array}\\\\

\begin{array}{rlll}

n+18&=&32\;\; therefore\\

n&=&14

\end{array}\\$$

check 14+18=32 and 5*14+10*18=70+180=250=$250 correct

So Sheila has 14 nickels

Melody Aug 3, 2014