Show that 3 - 2x^2 + 11x + 12 / x^2 +7x +12 can be simplified to x+6 / x+3
thx
\(3-\dfrac{2x^2+11x+12}{x^2+7x+12}\\ =3-\dfrac{(2x+3)(x+4)}{(x+3)(x+4)}\\ =3-\dfrac{2x+3}{x+3}\;,\;x\neq-4\\ =\dfrac{3x+9}{x+3}-\dfrac{2x+3}{x+3}\;,\;x\neq-4\\ =\dfrac{x+6}{x+3}\;,\;x\neq-4\)
The answer you wanted :)