+0  
 
+1
84
1
avatar+369 

 

smileysmileysmiley

qualitystreet  May 16, 2018
 #1
avatar+937 
+1

Hi QS!

 

Since the two shapes are similar, we can set up the following relationship:

 

Assumption 1: triangle ABE is similar to ACE, CD and BE is parallel 

 

\(\frac{15}{15+3}=\frac{10}{10+x}\\ 15(10+x)=10\cdot{18}\\ 150+15x=180\\ 15x=30\\ x=2\)

 

Assumption 2: triangle ABE is similar to ACE, CD and BE are not paralle

 

\(\frac{10}{15+3}=\frac{15}{10+x}\\ 10(10+x)=15\cdot18\\ 100+10x=270\\ 10x=170\\ x=17\)

 

I hope this helped,

 

Gavin

GYanggg  May 16, 2018
edited by GYanggg  May 16, 2018

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