#1**+1 **

Hi QS!

Since the two shapes are similar, we can set up the following relationship:

Assumption 1: triangle ABE is similar to ACE, CD and BE is parallel

\(\frac{15}{15+3}=\frac{10}{10+x}\\ 15(10+x)=10\cdot{18}\\ 150+15x=180\\ 15x=30\\ x=2\)

Assumption 2: triangle ABE is similar to ACE, CD and BE are not paralle

\(\frac{10}{15+3}=\frac{15}{10+x}\\ 10(10+x)=15\cdot18\\ 100+10x=270\\ 10x=170\\ x=17\)

I hope this helped,

Gavin

GYanggg
May 16, 2018