​Similar to that one confused

Two number cubes, when rolled,

will produce:                                      To find the expected number of times in 48 rolls, multiply each by 48

a sum of 2, 1/36^th of the time                       x 48  =  48/36  =  1.3333...

a sum of 3, 2/36^th of the time                       x 48  =  96/36  =  2.6666...

a sum of 4, 3/36^th of the time                       x 48  =  144/36  =  4...

a sum of 5, 4/36^th of the time                       x 48  =  192/36  =  5.3333...

a sum of 6, 5/36^th of the time                       x 48  =  240/36  =  6.6666...

a sum of 7, 6/36^th of the time                       x 48  =  288/36  =  8...

a sum of 8, 5/36^th of the time                       x 48  =  240/36  =  6.6666...

a sum of 9, 4/36^th of the time                        x 48  =  192/36  =  5.3333...

a sum of 10, 3/36^th of the time                      x 48  =  144/36  =  4...

a sum of 11, 2/36^th of the time                      x 48  =  96/36  =  2.6666...

a sum of 12, 1/36^th of the time                     x 48  =  48/36  =  1.3333...

 

Only answer (c) has the exact value