+73 since PQ and JL are parallel, we can determine that triangles KJL and KPQ are similar.
now, we can use the similar triangle ratios to help us find x:
\(\frac{x-6}{x-6+3} = \frac{x-6}{x-3}\)
and we also have
\(\frac{x}{x+5}\)
we know that these two equal each other. so we get an equation:
\(\frac{x-6}{x-3}= \frac{x}{x+5}\)
let's cross multiply, and then continue simplifying -
\((x-6)(x+5) = (x-3)x\)
\(x^2-x-30 = x^2-3x\)
\(2x = 30\)
\(x=15\), which is option D
as you can see, the equation ended up simplifying quite nicely!
hope this helped! please let me know if you are still confused :)
