In a press conference before the All-Star Game, eight All-Stars will be taking questions. Three are Cubs, three are Red Sox, and two are Yankees. If teammates insist on sitting together, how many ways can the eight All-Stars be seated in a row?

Guest Apr 19, 2018

I would guess that there would be 314 ways to arrange them.

I have seen this question a while back and that was what I calculated. Nobody answered back so i dont know if it was right.


somebody correct me if im wrong.

Donut  Apr 19, 2018
edited by Donut  Apr 19, 2018

OK, I will try this: 

You can group the 8 into 3 different groups. And, as groups, you can seat them in:

3! = 6 ways. But the 3 Cubs can be seated in 3! ways, the 3 Red Sox can also be seated in 3! ways, and the 2 Yankees can be seated in 2! ways. So, altogether, they can be seated in:

3! x 3! x 3! x 2! = 432 ways. Somebody should check this.

Guest Apr 19, 2018

7 Online Users


New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.