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{(5x+1)/(x^2 + x -2)}- {3/(x+2)} 

Guest Sep 15, 2014

Best Answer 

 #1
avatar+92623 
+5

$$\\\frac{5x+1}{x^2 + x -2}- \frac{3}{x+2} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3}{x+2} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3(x-1)}{(x+2)(x-1)} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3x-3}{(x+2)(x-1)} \\\\
\frac{5x+1}{(x+2)(x-1)}+ \frac{-3x+3}{(x+2)(x-1)} \\\\
\frac{5x+1-3x+3}{(x+2)(x-1)}\\\\
\frac{2x+4}{(x+2)(x-1)}\\\\
\frac{2(x+2)}{(x+2)(x-1)}\\\\
\frac{2}{x-1}\\\\$$

Melody  Sep 16, 2014
 #1
avatar+92623 
+5
Best Answer

$$\\\frac{5x+1}{x^2 + x -2}- \frac{3}{x+2} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3}{x+2} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3(x-1)}{(x+2)(x-1)} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3x-3}{(x+2)(x-1)} \\\\
\frac{5x+1}{(x+2)(x-1)}+ \frac{-3x+3}{(x+2)(x-1)} \\\\
\frac{5x+1-3x+3}{(x+2)(x-1)}\\\\
\frac{2x+4}{(x+2)(x-1)}\\\\
\frac{2(x+2)}{(x+2)(x-1)}\\\\
\frac{2}{x-1}\\\\$$

Melody  Sep 16, 2014

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