How would i simplify and solve for the non permissible values of this rational expression?

Guest Aug 8, 2018

#1**+1 **

\(\frac{q+2x}{q-4x}\div\frac{q^2-4x^2}{q^2-16x^2}\) | Original, unsimplified equation. |

\(\frac{q+2x}{q-4x}\cdot\frac{q^2-16x^2}{q^2-4x^2}\) | Dividing by a fraction is equal to multiplying by its reciprical. |

\(\frac{q+2x}{q-4x}\cdot\frac{(q+4x)(q-4x)}{(q+2x)(q-2x)}\) | Applying difference of squares: \(a^2-b^2=(a+b)(a-b)\). |

\(\frac{(q+4x)}{(q-2x)}\) | Cancelling out like terms. |

\((q+4x)\div(q-2x)\) | Final simplified expression |

I hope this helped,

Gavin

GYanggg Aug 9, 2018