+83 What is X?
sin 41° = cos x
Should be one of my final questions.
I'm just awful at trig.
+9481 sin θ = cos( 90° - θ )
So.....
sin 41° = cos( 90° - 41° )
sin 41° = cos x Plug in cos( 90° - 41° ) for sin 41°
cos( 90° - 41° ) = cos x
cos 49° = cos x
49° = x 
+9481 With problems like these just remember that
sin θ = cos( 90° - θ ) This is always true for any value of θ .
You can always replace a sin x with a cos(90 - x) because they are equal.
So in this case we replaced a sin 41° with a cos( 90° - 41° ) because they are equal.
Also remember that...
cos θ = sin( 90° - θ ) This is also true for any value of θ .
(All the "co-functions" are like this: sine and cosine, secant and cosecant, and tangent and cotangent.)
This is kinda confusing, I know! It takes some getting used to!!
